The inverse of a scalar multiple is the reciprocal times the inverse.

Created almost 9 years ago, updated about 8 hours ago

For invertible $A$ and nonzero scalar $c$, $(cA)^{-1}=c^{-1}A^{-1}$. Multiplying gives $(cA)(c^{-1}A^{-1})=I$. The condition $c\ne0$ is essential; the zero matrix is not invertible in positive dimension.

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