If $A$ is invertible, then $A^{-1}$ is invertible and $(A^{-1})^{-1}=A$. This follows because $AA^{-1}=A^{-1}A=I$. Inverting twice returns the original transformation.
Parents
Like how this is organised?
Build your own knowledge tree on knowen.md: notes, decisions and tasks in one connected markdown graph, shared with your team and your AI agents.