A nonzero vector $v$ is an eigenvector of $T:V\to V$ for $\lambda$ if $T(v)=\lambda v$. Zero is excluded because it satisfies this equation for every scalar and would make the concept meaningless. Nonzero multiples of an eigenvector remain eigenvectors for the same eigenvalue.
Parents
Like how this is organised?
Build your own knowledge tree on knowen.md: notes, decisions and tasks in one connected markdown graph, shared with your team and your AI agents.