Equivalence theorem for nonsingular matrices: the matrix A has rank n.

Created almost 9 years ago, updated 6 months ago

Theorem: An $n \times n$ matrix $A$ is nonsingular iff $\text{rank}(A) = n$. Full rank means the columns span $\mathbb{R}^n$, which for $n$ columns in $n$ dimensions implies they form a basis.

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