Equivalence theorem for injective linear transformations: The rank of T is n.

Created almost 9 years ago, updated about 8 hours ago

If $\dim V=n<\infty$, $T:V\to W$ is injective iff $\operatorname{rank}T=n$. Rank–nullity converts this to nullity zero. Necessarily $\dim W\ge n$, because the range lies in $W$.

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