Equivalence theorem for injective linear transformations: The nullity of T is 0.

Created almost 9 years ago, updated about 8 hours ago

For a linear map with finite-dimensional domain, injectivity is equivalent to nullity zero. Nullity is the dimension of the kernel, and the only zero-dimensional subspace is $\{0\}$. Rank–nullity then gives rank equal to the domain dimension.

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