A linear transformation is surjective if and only if the image of a basis is a spanning set

Created almost 9 years ago, updated about 8 hours ago

For a basis $B$ of $V$, the image list $T(B)$ always spans the range. It spans the codomain exactly when $T$ is surjective. If $T$ is also injective, this image list is a basis of the codomain.

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