The inverse of a composition reverses the order

Created almost 9 years ago, updated about 8 hours ago

For invertible composable maps $A,B$, $(A\circ B)^{-1}=B^{-1}\circ A^{-1}$. Also, for an invertible operator and nonzero scalar $c$, $(cA)^{-1}=c^{-1}A^{-1}$. These laws have the same hypotheses as the corresponding matrix formulas.

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