Theorem (Basic Properties of Vector Spaces): Let $V$ be a vector space over $F$. Then:
- $0v = 0$ — The scalar zero times any vector equals the zero vector.
- $a0 = 0$ — Any scalar times the zero vector equals the zero vector.
- $(-1)v = -v$ — Multiplying by $-1$ gives the additive inverse.
- If $av = 0$, then $a = 0$ or $v = 0$ — No zero divisors.
- The zero vector is unique.
- Additive inverses are unique.
Proof sketch for (1): $0v = (0+0)v = 0v + 0v$ by D2. Adding $-(0v)$ to both sides gives $0 = 0v$. $\blacksquare$
Proof sketch for (4): If $a \neq 0$, multiply both sides of $av = 0$ by $a^{-1}$: $a^{-1}(av) = a^{-1} \cdot 0$, so $(a^{-1}a)v = 0$, hence $1 \cdot v = 0$, so $v = 0$. $\blacksquare$
Application: These properties are used constantly in proofs. For instance, property (4) is key in proving that eigenvectors corresponding to distinct eigenvalues are linearly independent.
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- The 0 vector is unique.A vector space has a unique additive identity. If $0$ and $0& 39;$ both act as identities, then $0=0+0& 39;=0& 39;$....
- The additive inverse of a vector is unique.The additive inverse of a vector is unique. If $v+w=0$ and $v+z=0$, then $w=w+(v+z)=(w+v)+z=z$. Thus every vector has...
- The 0 scalar multiplied by any vector equals the 0 vector.For any vector $v$, $0v=0 V$. Since $(0+0)v=0v+0v$, canceling $0v$ gives the result. The zero scalar and zero vector...
- The 0 vector multiplied by any scalar equals the 0 vector.For every scalar $c$, $c0 V=0 V$. Distribute over $0 V+0 V$ to obtain $c0 V=c0 V+c0 V$, then subtract. This is a...
- If the product of a vector and a scalar is 0In a vector space over a field , $cv=0$ implies $c=0$ or $v=0$. If $c\ne0$, multiply by $c^{-1}$ to obtain $v=0$....
- The additive inverse of a vector equals the vector multiplied by -1.Distributivity gives $v+(-1)v=(1+(-1))v=0v=0$. Thus $(-1)v$ is the additive inverse of $v$, so $-v=(-1)v$....
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