The distance between vectors is $d(x,y)=\|x-y\|$. It is symmetric, nonnegative, zero exactly when $x=y$, and satisfies $d(x,z)\le d(x,y)+d(y,z)$. For $(1,2)$ and $(4,6)$, the distance is $\sqrt{3^2+4^2}=5$.
Parents
Like how this is organised?
Build your own knowledge tree on knowen.md: notes, decisions and tasks in one connected markdown graph, shared with your team and your AI agents.