The standard inner product of a vector with itself is 0 only for the 0 vector

Created almost 9 years ago, updated about 8 hours ago

The sum $\langle x,x\rangle=\sum_j|x_j|^2$ is zero iff every coordinate is zero. This is positive definiteness. Without conjugation the claim fails over $\mathbb C$: $1^2+i^2=0$ although $(1,i)\ne0$.

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