For any fixed row $i$, $\det A=\sum_j a_{ij}C_{ij}$, where $C_{ij}=(-1)^{i+j}\det A_{\widehat i,\widehat j}$. The value is independent of the selected row. Choose one containing many zeros to reduce work. The expansion follows by grouping permutation terms by their selected column in row $i$.
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