Distinct eigenvalues of a Hermitian matrix have orthogonal eigenvectors.

Created almost 9 years ago, updated 6 months ago

Theorem: Eigenvectors corresponding to distinct eigenvalues of a Hermitian matrix are orthogonal. If $Av_1 = \lambda_1 v_1$ and $Av_2 = \lambda_2 v_2$ with $\lambda_1 \neq \lambda_2$, then $v_1^*v_2 = 0$.

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