For an eigenvalue $\lambda$ of $A$, its eigenspace is $E_\lambda=\ker(A-\lambda I)$. It includes the zero vector and all eigenvectors for $\lambda$. Eigenvectors themselves must be nonzero. Find a basis by row-reducing $A-\lambda I$ and solving its homogeneous system.
Parents
Like how this is organised?
Build your own knowledge tree on knowen.md: notes, decisions and tasks in one connected markdown graph, shared with your team and your AI agents.