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Added full rank equivalence
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# Equivalence theorem for nonsingular matrices: the matrix A has rank n.Put content here**Theorem:** An $n \times n$ matrix $A$ is nonsingular iff $\text{rank}(A) = n$. Full rank means the columns span $\mathbb{R}^n$, which for $n$ columns in $n$ dimensions implies they form a basis. # Parents * Nonsingular matrices and equivalences
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