Write $A=[a_1\ \cdots\ a_n]$ by columns and write $B$ by rows $r_1,\ldots,r_n$. Then $AB=\sum_{k=1}^n a_kr_k$, a sum of outer products. Entry $ij$ is $\sum_k(a_k)_i(r_k)_j=\sum_k a_{ik}b_{kj}$. This is a block-level row-by-column rule.
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